Give a mechanism for this reaction. (Hint: The secondary carbocation formed in step II rearranges to a more stable tertiary carbocation by a hydride ion shift from 3rd carbon atom)
Give a mechanism for this reaction. (Hint: The secondary carbocation formed in step II rearranges to a more stable tertiary carbocation by a hydride ion shift from 3rd carbon atom)

Solution:

The following procedure is involved in the above-mentioned steps of the reaction:

Step 1: Protonation

Step 2: Forming 2 ° carbonation by eliminating the water molecule

Step 3: Rearranging by the shifting hydride–ion

Step 4: Nucleophilic attack