Answer : Since the committee of 11 is to be formed from 6 teachers and 8 students.
- Forming a committee with exactly 4 teachers Choosing 4 teachers out of 6 in 6C4 Remaining 7 from 8 students in 8C7 ways.
Thus, total ways in (i) are 6C4 8C7 ways.
- The number of ways in this case is
- 4 teachers and 7 students
- 5 teachers and 6 students
- 6 teachers and 5 students
= 6C4 X8C7+ 6C5 X8C6 X6C6 X8C5
= 344 ways