As per the given question,
If $x=a(\theta-\sin \theta)$ and $y=a(1+\cos \theta)$ find $\frac{d y}{d x}$, at $\theta=\frac{\pi}{3}$.
If $x=a(\theta-\sin \theta)$ and $y=a(1+\cos \theta)$ find $\frac{d y}{d x}$, at $\theta=\frac{\pi}{3}$.
As per the given question,