Age (in years) | Number of policy holder |
Below 20 | 2 |
Below 25 | 6 |
Below 30 | 24 |
Below 35 | 45 |
Below 40 | 78 |
Below 45 | 89 |
Below 50 | 92 |
Below 55 | 98 |
Below 60 | 100 |
Solution:
Class interval Frequency Cumulative recurrence
15-20 2 2
20-25 4 6
25-30 18 24
30-35 21 45
35-40 33 78
40-45 11 89
45-50 3 92
50-55 6 98
55-60 2 100
Given information: n = 100 and n/2 = 50
Middle class = 35-45
Then, at that point, l = 35, cf = 45, f = 33 and h = 5
\[\begin{array}{*{35}{l}}
Middle\text{ }=\text{ }35+\left( \left( 50-45 \right)/33 \right)\text{ }\times \text{ }5 \\
~ \\
=\text{ }35\text{ }+\text{ }\left( 5/33 \right)5 \\
~ \\
=\text{ }35.75 \\
\end{array}\] Thusly, the middle age = 35.75 years.