Monthly consumption(in units) | No. of customers |
65-85 | 4 |
85-105 | 5 |
105-125 | 13 |
125-145 | 20 |
145-165 | 14 |
165-185 | 8 |
185-205 | 4 |
Solution:
Track down the aggregate recurrence of the given information as follows:
Class Interval Frequency Cumulative recurrence
65-85 4 4
85-105 5 9
105-125 13 22
125-145 20 42
145-165 14 56
165-185 8 64
185-205 4 68
N=68
From the table, it is seen that, n = 68 and thus n/2=34
Thus, the middle class is 125-145 with total recurrence = 42
Where, l = 125, n = 68, Cf = 22, f = 20, h = 20
Middle is determined as follows:
Ncert arrangements class 10 part 14-1
=125+((34−22)/20) × 20
=125+12 = 137
Along these lines, middle = 137
To compute the mode:
Modular class = 125-145,
f1=20, f0=13, f2=14 and h = 20
Mode recipe:
\[\begin{array}{*{35}{l}}
Mode\text{ }=\text{ }l+\text{ }\left[ \left( f1-f0 \right)/\left( 2f1-f0-f2 \right) \right]\times h \\
~ \\
Mode\text{ }=\text{ }125\text{ }+\text{ }\left( \left( 20-13 \right)/\left( 40-13-14 \right) \right)\times 20 \\
~ \\
=125+\left( 140/13 \right) \\
~ \\
=125+10.77 \\
~ \\
=135.77 \\
\end{array}\]
Consequently, mode = 135.77
Compute the Mean:
Class Interval fi xi \[di=xi-a~~ui=di/h~fiui\]
65-85 4 75 -60 -3 -12
85-105 5 95 -40 -2 -10
105-125 13 115 -20 -1 -13
125-145 20 135 0 0 0
145-165 14 155 20 1 14
165-185 8 175 40 2 16
185-205 4 195 60 3 12
Total fi= 68 Sum fiui= 7
\[x\text{ }=a+h\text{ }\sum fiui/\sum fi\text{ }=135+20\left( 7/68 \right)\]
Mean=137.05 For this situation, mean, middle and mode are more/less equivalent in this conveyance.