Power consumption in a day = 10 units
Power consumption per hour = 2 units
Power consumption = 2 units = 2 kW = 2000 J/s
Power consumption in resistors, P = VI
Which gives I = 9A
We know that resistance, R = ρ l/A
Substituting the values we get, resistance = 4 J/s
This is used in the calculation of power loss in Al wire = 6.4 J/s
Fractional loss in the second wire due to Joule heating is = 0.32%