Solution:
For an A.P series we all know that;
an = a+(n−1)d
a17 = a+(17−1)d
a17 = a +16d
Similarly,
a10 = a+9d
As stated in the question,
a17 − a10 = 7
Therefore,
(a +16d)−(a+9d) = 7
7d = 7
d = 1
Therefore, 1 is the common difference.
If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.
If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.