Solution:

Answer: C. $P(B \mid A)>P(B)$
Given in the question that, thus evaluating the value of parameters we have

$P(A \mid B)>P(A)$

$\therefore \frac{P(A \cap B)}{P(B)}>P(A)$

$P(A \cap B)>P(A) \cdot P(B)$

$\frac{P(A \cap B)}{P(A)}>P(B)$

$P(B \mid A)>P(B)$

Hence, option C is correct