Answer:
Given,
Sum of first three terms is 24
Assume the first three terms are a – d, a, a + d [where a is the first term and d is the common difference]
Sum of first three terms is a – d + a + a + d = 24
3a = 24
a = 8
It is given that the product of three terms is 440
So a3 – ad2 = 440
Substitute the value of a = 8,
83 – 8d2 = 440
512 – 8d2 = 440
72 = 8d2
d = 3 or d = – 3
Hence, the given terms are a – d, a, a + d which is 5, 8, 11