Given edge of the cube, a = 7 cm

Diameter of the hemisphere, d = 7 cm

Radius, r = d/2 = 7/2 = 3.5 cm

Surface area of the hemisphere = 2r²

= 2×(22/7)×3.5²

= 44×12.25/7

= 539/7

= 77 cm²

Surface area of the cube = 6a²

= 6×7²

= 6×49

= 294 cm²

Surface area of base of hemisphere = r²

= (22/7)×3.5²

= 22×12.25/7

= 38.5 cm²

Surface area of the solid = surface area of the cube + surface area of hemisphere – surface area of the base of hemisphere

= 294+77-38.5

= 332.5 cm²

Hence the surface area of the solid is 332.5 cm².