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A quadratic polynomial whose zeroes are 5 and -3, is (a) $x^{2}+2 x-15$ (b) $x^{2}-2 x+15$ (c) $x^{2}-2 x-15$ (d) none of these
A quadratic polynomial whose zeroes are 5 and -3, is (a) $x^{2}+2 x-15$ (b) $x^{2}-2 x+15$ (c) $x^{2}-2 x-15$ (d) none of these
CBSE | Class 10 | Excercise 2D | Maths | Polynomials | RS Aggarwal
A quadratic polynomial whose zeroes are 5 and -3, is (a) $x^{2}+2 x-15$ (b) $x^{2}-2 x+15$ (c) $x^{2}-2 x-15$ (d) none of these

(c) $x^{2}-2 x-15$

Since, the zeroes are 5 and $-3$.

$\alpha=5$ and $\beta=-3$

Therefore, sum of the zeroes, $\alpha+\beta=5+(-3)=2$

product of the zeroes, $\alpha \beta=5 \times(-3)=-15$

The polynomial will be $\mathrm{x}^{2}-(\alpha+\beta) \mathrm{x}+\alpha \beta$

$\therefore$ The required polynomial is $x^{2}-2 x-15$.

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