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Find the coordinates of the point where the diagonals of the parallelogram formed by joining the points $(-2,-1)$,$(1,0)$,$(4,3)$ and$(1,2)$ meet.
Find the coordinates of the point where the diagonals of the parallelogram formed by joining the points $(-2,-1)$,$(1,0)$,$(4,3)$ and$(1,2)$ meet.
CBSE | Class 10 | Co-ordinate Geometry | Exercise 14.3 | Maths | RD Sharma
Find the coordinates of the point where the diagonals of the parallelogram formed by joining the points $(-2,-1)$,$(1,0)$,$(4,3)$ and$(1,2)$ meet.

Let’s consider A$(-2,-1)$,B$(1,0)$,C$(4,3)$ and D$(1,2)$ are the given points.

Let’s take P(x, y) be the point of intersection of the diagonals of the parallelogram formed by the given points.

As We know that, diagonals of a parallelogram bisect each other. Therefore,

$x=\frac{2+4}{2}$

$\Rightarrow x=\frac{2}{2}=1$

$y=\frac{-1+3}{2}=\frac{2}{2}=1$

Hence, the coordinates of P are $(1,1)$

i

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