Given two mutually exclusive events A and B such that P (A) = 1/2 and P (B) = 1/3, find P (A or B).
Given two mutually exclusive events A and B such that P (A) = 1/2 and P (B) = 1/3, find P (A or B).

A and B are two mutually exclusive events is given

P (A) = 1/2 and P (B) = 1/3

We need to find P (A ‘or’ B).

P (A or B) = P (A ∪ B)

So by definition of mutually exclusive events we know,

P (A ∪ B) = P (A) + P (B)

= 1/2 + 1/3

= 5/6

∴ P (A ∪ B) is 5/6