The circumference of the base of a 12 m high conical tent is 66 m. Find the volume of the air contained in it.
The circumference of the base of a 12 m high conical tent is 66 m. Find the volume of the air contained in it.

Circumference of the base (c) = 66 m

Height of the conical tent (h) = 12 m

Radius

\[=\text{ }c/2\pi \text{ }=\text{ }66/\text{ }2\pi \text{ }=\text{ }\left( 33\text{ x }7 \right)/22\text{ }=\text{ }21/2\text{ }=\text{ }10.5\text{ }m\]

the volume of the cone tent

\[\begin{array}{*{35}{l}}

=\text{ }1/3\text{ }\pi {{r}^{2}}h  \\

=\text{ }1/3\text{ x }22/7\text{ x }{{\left( 21/2 \right)}^{2}}~x\text{ }12  \\

=\text{ }1386\text{ }{{m}^{3}}  \\

\end{array}\]

Therefore, the volume of air contained is 1386 m3.