Therefore, the required probability distribution is
Two biased dice are thrown together. For the first die \[\mathbf{P}\left( \mathbf{6} \right)\text{ }=\text{ }\mathbf{1}/\mathbf{2}\], the other scores being equally likely while for the second die, \[\mathbf{P}\left( \mathbf{1} \right)\text{ }=\text{ }\mathbf{2}/\mathbf{5}\]and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.
Two biased dice are thrown together. For the first die \[\mathbf{P}\left( \mathbf{6} \right)\text{ }=\text{ }\mathbf{1}/\mathbf{2}\], the other scores being equally likely while for the second die, \[\mathbf{P}\left( \mathbf{1} \right)\text{ }=\text{ }\mathbf{2}/\mathbf{5}\]and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.