Here, random variable \[X\text{ }=\text{ }0,\text{ }1,\text{ }2\]
\[P\left( X\text{ }=\text{ }2 \right)\text{ }=\text{ }P\left( 4 \right).P\left( 4 \right)\text{ }=\text{ }1/10\text{ }x\text{ }1/10\text{ }=\text{ }1/100\]
Now, we know \[V\left( X \right)\text{ }=\text{ }E({{X}^{2}})\text{ }\text{ }{{\left[ E\left( X \right) \right]}^{2}}\]
Therefore, the required variance = \[0.18\].