Ten coins are tossed. What is the probability of getting at least 8 heads?
Ten coins are tossed. What is the probability of getting at least 8 heads?

Here we have, \[n=10\], \[p=1/2\] and \[q=1-1/2=1/2\]

\[P\left( X\text{ }\ge \text{ }8 \right)\text{ }=\text{ }P\left( x\text{ }=\text{ }8 \right)\text{ }+\text{ }P\left( x\text{ }=\text{ }9 \right)\text{ }+\text{ }P\left( x\text{ }=\text{ }10 \right)\]

Therefore, the required probability is \[7/128\].