A bag contains $4$ red, $5$ black and $6$ white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is:
A bag contains $4$ red, $5$ black and $6$ white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is:

(iii) Total number of black balls are $5$

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Therefore, the probability of drawing black ball P(E) $=5/15=1/3$

As We know that sum of probability of occurrence of an event and probability of non-occurrence of an event is $1$.

$P(E)+P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1$

$\frac{1}{3}+P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1$

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-\frac{1}{3}$

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=\frac{2}{3}$

Hence, the probability of drawing a ball that is not black is $2/3$

(iv) Total number of red or white balls $4+6=10$

As We know that Probability = Number of favorable outcomes/ Total number of outcomes

Hence , the probability of drawing a white or red ball $=10/15=2/3$