A box is given which contains $5$ red marbles, $8$ white marbles and $4$ green marbles. if One marble is taken out of the box at random. Then What is the probability that the marble taken out will be (i) red (ii) not green
A box is given which contains $5$ red marbles, $8$ white marbles and $4$ green marbles. if One marble is taken out of the box at random. Then What is the probability that the marble taken out will be (i) red (ii) not green

Given that,

We have A box which containing 5 red, 8 white and 4 green marbles.

Therefore, the total no. of possible outcomes $=17$ ($5$ red $+8$ white $+4$ green)

(i) Let E be the Event of getting a red marble

So, Number of favorable outcomes $=5$ (as $5$ red marbles)

As we know Probability, P(E) = Number of favorable outcomes/ Total number of outcomes

P(E) $=5/17$

(ii) Let E be the event of getting a green marble

Therefore, Number of favorable outcomes $=4$ (as $4$ green marbles)

As we know, Probability, P(E) = Number of favorable outcomes/ Total number of outcomes

P(E) $=4/17$

Now,
Event of getting not a green marble

Therefore, we know that,

Thus , the probability that the marble taken out is not green is $13/17$.