Solution:

As, \[\vartriangle CPQ\text{ }\sim\text{ }\vartriangle CAB\text{ }by\text{ }AA\] criterion for similarity

We have,

\[CP/AC\text{ }=\text{ }CQ/CB\]

\[CP/AC\text{ }=\text{ }4.8/8.4\text{ }=\text{ }4/7\]

Since,\[AC\text{ }is\text{ }7\]parts and \[CP\text{ }is\text{ }4\] parts, then \[PA\text{ }is\text{ }3\]parts.

Hence, \[AC\text{ }=\text{ }7/3\text{ }x\text{ }PA\text{ }=\text{ }\left( 7/3 \right)x\]