Given that the numbers are $1,2,2,3,3, 3,4,4,4,4$
So, Total number of possible outcomes $=10$
$Averageoftheno’s=\frac{sumofnumbers}{tota\ln umber}$
$=\frac{1+2+2+3+3+3+4+4+4+4}{10}$
$=30/10$
$=3$
Now, let’s E be the event of getting 3.
Therefore, Number of favorable outcomes $=3(3,3,3)$
P(E) = Number of favorable outcomes/ Total number of outcomes
P(E) $=3/10$
Thus, the probability that a number selected at random will be the average is $3/10$.