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A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, $1,2,3,….,12$ as shown in figure. What is the probability that it will point to:(iii) a number which is multiple of $3$? (iv) an even number?
A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, $1,2,3,….,12$ as shown in figure. What is the probability that it will point to:(iii) a number which is multiple of $3$? (iv) an even number?
CBSE | Class 10 | Exercise 13.1 | Maths | Maths | Probability | RD Sharma
A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, $1,2,3,….,12$ as shown in figure. What is the probability that it will point to:(iii) a number which is multiple of $3$? (iv) an even number?

(iii) So, Favorable outcomes i.e. to get a multiple of $3$ are $3,6,9,$ and $12$

Therefore, total number of favorable outcomes i.e. to get a multiple of $3$ is $4$

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Hence, the probability of getting multiple of $3=4/12=1/3$

(iv) Now, Favorable outcomes i.e. to get an even number are $2,4,6,8,10,$ and $12$

Therefore, total number of favorable outcomes i.e. to get an even number is $6$

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Hence, the probability of getting an even number $=6/12=1/2$

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