The correct Option is A
As we know range is given as $\frac{u^{2} \sin 2 \theta}{g}$ so $g \infty u^{2}$
So, $g_{\text {planet }}=\left(\frac{3}{5}\right)^{2}\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)=3.5 \mathrm{~m} / \mathrm{s}^{2}$
The correct Option is A
As we know range is given as $\frac{u^{2} \sin 2 \theta}{g}$ so $g \infty u^{2}$
So, $g_{\text {planet }}=\left(\frac{3}{5}\right)^{2}\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)=3.5 \mathrm{~m} / \mathrm{s}^{2}$