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In a match between A and B: \[\left( \mathbf{i} \right)\] the probability of winning of A is \[\mathbf{0}.\mathbf{83}\]. What is the probability of winning of B? \[\left( \mathbf{ii} \right)\] the probability of losing the match is \[\mathbf{0}.\mathbf{49}\] for B. What is the probability of winning of A?
In a match between A and B: \[\left( \mathbf{i} \right)\] the probability of winning of A is \[\mathbf{0}.\mathbf{83}\]. What is the probability of winning of B? \[\left( \mathbf{ii} \right)\] the probability of losing the match is \[\mathbf{0}.\mathbf{49}\] for B. What is the probability of winning of A?
CBSE | Class 10 | Exercise 13.2 | Selina | Statistics and Probability
In a match between A and B: \[\left( \mathbf{i} \right)\] the probability of winning of A is \[\mathbf{0}.\mathbf{83}\]. What is the probability of winning of B? \[\left( \mathbf{ii} \right)\] the probability of losing the match is \[\mathbf{0}.\mathbf{49}\] for B. What is the probability of winning of A?

Solution:

\[\left( i \right)\]We know that,

The probability of winning of A \[+\]Probability of losing of A \[=\text{ }1\]

And,

Probability of losing of A \[=\] Probability of winning of B

Therefore,

Probability of winning of A \[+\] Probability of winning of B \[=\text{ }10.83\text{ }+\] Probability of winning of B \[=\text{ }1\]

Hence, probability of winning of B \[=\text{ }1\text{ }\text{ }0.83\text{ }=\text{ }0.17\]

\[\left( ii \right)\] We know that,

Probability of winning of B\[~+\]  Probability of losing of B \[=\text{ }1\]

And, probability of losing of B \[=\]Probability of winning of A

Therefore,

Probability of winning of A \[=\text{ }0.49\]

i

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