\[\left( iii \right)\text{ }E\text{ }=\] event of getting a number not greater than \[4\text{ }=\text{ }\left\{ 1,\text{ }2,\text{ }3,\text{ }4 \right\}\]
So\[,\text{ }n\text{ }\left( E \right)\text{ }=\text{ }4\]
Then, probability of getting a number not greater than \[4\text{ }=~n\left( E \right)/\text{ }n(s)\text{ }=~4/6\text{ }=\text{ }2/3\]