According to the question, three dice are rolled over.
By using the formula of probability, we get,
P (E) = favourable outcomes / total possible outcomes
So, we have to find the probability of getting the same number on all the three dice
Total number of possible outcomes is $6^3=216$
n (S) = 216
Let E be the event of getting same number on all the three dice
E = {(1,1,1) (2,2,2) (3,3,3) (4,4,4) (5,5,5) (6,6,6)}
n (E) = 6
P (E) = n (E) / n (S)
= 6 / 216
= 1/36