\[\begin{array}{*{35}{l}}
x\text{ }+\text{ }5\text{ }>\text{ }4x\text{ }-\text{ }10 \\
x\text{ }+\text{ }5\text{ }-\text{ }5\text{ }>\text{ }4x\text{ }-\text{ }10\text{ }-\text{ }5 \\
x\text{ }>\text{ }4x\text{ }-\text{ }15 \\
4x\text{ }-\text{ }15\text{ }<\text{ }x \\
4x\text{ }-\text{ }15\text{ }-\text{ }x\text{ }<\text{ }x\text{ }-\text{ }x \\
3x\text{ }-\text{ }15\text{ }<\text{ }0 \\
3x\text{ }-\text{ }15\text{ }+\text{ }15\text{ }<\text{ }0\text{ }+\text{ }15 \\
3x\text{ }<\text{ }15 \\
\end{array}\]
Dividing both sides by 3, we get
\[\begin{array}{*{35}{l}}
3x/3\text{ }<\text{ }15/3 \\
x\text{ }<\text{ }5 \\
\end{array}\]
∴ The solution of the given inequation is (-∞, 5).