When a coin is tossed the possible outcomes are either a Head $\left( H \right)$ or Tail $\left( T \right)$.
Here, coin is tossed three times then the sample space contains,
$S{\text{ }} = {\text{ }}\left\{ {HHH,{\text{ }}HHT,{\text{ }}HTH,{\text{ }}THH,{\text{ }}TTH,{\text{ }}HTT,{\text{ }}TTT,{\text{ }}THT} \right\}$
And $n\left( S \right){\text{ }} = {\text{ }}8$.
(v) no head
Suppose $E$ be the event of getting no heads.
So, $n\left( E \right){\text{ }} = {\text{ }}1$
Then, the probability of the event is
$P(E) = \frac{{n(E)}}{{n(S)}}$
$P(E) = \frac{1}{8}$
(vi) $3$ tails
Suppose $F$ be the event of getting $3$ tails.
So, $n\left( F \right){\text{ }} = {\text{ }}1$
Then, the probability of the event is
$P(F) = \frac{{n(F)}}{{n(S)}}$
$P(F) = \frac{1}{8}$