Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements. (i) Both the compounds form the same product on treatment with alcoholic KOH. (ii) Both the compounds form the same product on treatment with aq.NaOH. (iii) Both the compounds form the same product on reduction. (iv) Both the compounds are optically active.
Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements. (i) Both the compounds form the same product on treatment with alcoholic KOH. (ii) Both the compounds form the same product on treatment with aq.NaOH. (iii) Both the compounds form the same product on reduction. (iv) Both the compounds are optically active.

Option (i) and (iii) are the answers.

They give ethyne on treatment with alcoholic $\mathrm{KOH}$.

$
\mathrm{CH}_{3} \mathrm{CHCl}_{2} \underset{\mathrm{KOH}}{\stackrel{\text { alc. }}{\longrightarrow}} \mathrm{CH} \equiv \mathrm{CH}+2 \mathrm{KCl}+2 \mathrm{H}_{2} \mathrm{O}$
$
\mathrm{Cl}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Cl} \stackrel{\text { alc. } \mathrm{KOH}}{\longrightarrow} \mathrm{CH} \equiv \mathrm{CH}+2 \mathrm{KCl}+\mathrm{H}_{2} \mathrm{O}$

On reduction with $\mathrm{Zn}$ dust in alcohol they give ethylene. $\mathrm{CH}_{3} \mathrm{CHCl}_{2}+\mathrm{Zn} \stackrel{\mathrm{CH}_{3} \mathrm{OH}}{\longrightarrow} \mathrm{CH}_{2}=\mathrm{CH}$

$
\mathrm{Cl}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Cl}+\mathrm{Zn} \stackrel{\mathrm{CH}_{3} \mathrm{OH}}{\longrightarrow} \mathrm{CH}_{2}=\mathrm{CH}_{2}$