If the ratio between 8 and 11 is the same as the ratio of 2x – y to x + 2y, find the value of 7x/ 9y.
If the ratio between 8 and 11 is the same as the ratio of 2x – y to x + 2y, find the value of 7x/ 9y.

\[\left( 2x\text{ }-\text{ }y \right)/\text{ }\left( x\text{ }+\text{ }2y \right)\text{ }=\text{ }8/11\]

On cross multiplying, we get

\[\begin{array}{*{35}{l}}

11\left( 2x\text{ }-\text{ }y \right)\text{ }=\text{ }8\left( x\text{ }+\text{ }2y \right)  \\

22x\text{ }\text{ }-11y\text{ }=\text{ }8x\text{ }+\text{ }16y  \\

14x\text{ }=\text{ }27y  \\

x/y\text{ }=\text{ }27/14  \\

\end{array}\]

So,

\[7x\text{ }/\text{ }9y\text{ }=\text{ }\left( 7\text{ }x\text{ }27 \right)/\text{ }\left( 9\text{ }x\text{ }14 \right)\text{ }=\text{ }3/2\]