Answer:
A function that represents SHM is written as
sin (2π/T t + ϕ)
We have, y = sin ωt – cos ωt
y = √2 sin (ωt – π/4)
The standard equation of SHM has:
y = a sin (2π/T t + ϕ)
Therefore, T = 2π/ω
Show that the motion of a particle represented by y = sin ωt – cos ωt is simple harmonic with a period of 2π/ω.
Show that the motion of a particle represented by y = sin ωt – cos ωt is simple harmonic with a period of 2π/ω.