The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45 degrees, its range will be a) 60 m b) 71 m c) 100 m d) 141 m
The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45 degrees, its range will be a) 60 m b) 71 m c) 100 m d) 141 m

Answer:

The correct answer is c) 100 m

Given:

The horizontal range of a projectile that is fixed at an angle to the horizontal plane $=15^{\circ}$
Range $=50 m$
In the first case range $=50= u ^{2} / g \left(\sin 2 \times 15^{\circ}\right)$
$50=\frac{2}{2 g }$
$\frac{ u ^{2}}{ g }=100$
In 2nd case range $=\frac{ u ^{2}}{ g \left(\sin 2 \times 45^{\circ}\right)}$

As we know  $\sin 90^{\circ}=1\right)$

$=\frac{100}{1}\left

$=100 m$