Solution:

From the articulation,

\[\begin{array}{*{35}{l}}

G\theta \text{ }=\text{ }\text{ }2.303\text{ }RT\text{ }logKeq  \\

~  \\

G\theta \text{ }for\text{ }the\text{ }response,\text{ }=\text{ }\left( 2.303 \right)\text{ }\left( 8.314\text{ }JK1\text{ }mol1\text{ } \right)\text{ }\left( 300\text{ }K \right)\text{ }log10  \\

~  \\

=\text{ }\text{ }5744.14\text{ }Jmol1  \\

~  \\

=\text{ }\text{ }5.744\text{ }kJ\text{ }mol1  \\

\end{array}\]