Solve the following inequalities graphically in two-dimensional plane: \[3x+4y\le 12\] - India Site

Solve the following inequalities graphically in two-dimensional plane: \[3x+4y\le 12\]

Class 11 | Exercise 6.2 | Linear Inequalities | Maths | NCERT

Solve the following inequalities graphically in two-dimensional plane: \[3x+4y\le 12\]

Solution:

The inequality given is \[3x+4y\le 12\]

Let us draw a solid line \[3x+4y=12\] in the graph (∵\[3x+4y=12\] is included in the given question)

Let us consider \[3x+4y\le 12\]

A point \[(0,0)\] is selected,

⇒ \[3\times (0)+4\times (0)\le 12\]

⇒ \[0\le 12\] (this is true)

Therefore, solution region of the given inequality is below the line\[3x+4y=12\]. (That is origin is included in the region)

The graph is represented as:

i

More Material

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Evaluate:

Evaluate:

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If $f(x) = |x| – 3,find\mathop {\lim }\limits_{x \to 3} f(x)$

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Let $\begin{array}{l} f(x) = \left\{ \begin{array}{l} \frac{|x-3|}{{(x-3)’}},x \ne 3\\ 0,x = 3 \end{array} \right.\\ \end{array}$ . Show that $\begin{array}{l} \mathop {\lim }\limits_{x \to 3} f(x) \end{array}$ does not exist.

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