Given condition, \[x2\text{ }+\text{ }6x\text{ }\text{ }10\text{ }=\text{ }0\]

Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }6\text{ }and\text{ }c\text{ }=\text{ }-\text{ }10\]

By quadratic equation, we have

Consequently, \[x\text{ }=\text{ }-\text{ }3\text{ }+\text{ }\surd 19\] or \[x\text{ }=\text{ }-\text{ }3\text{ }\text{ }\surd 19\]