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Write the general term in the expansion of (x2 – y x)12, x ≠ 0
Write the general term in the expansion of (x2 – y x)12, x ≠ 0
Binomial Theorem | CBSE | Class 11 | Exercise 8.2 | Maths
Write the general term in the expansion of (x2 – y x)12, x ≠ 0

The overall term \[Tr+1\] in the binomial development is given by \[Tr+1\text{ }=\text{ }n\text{ }C\text{ }r\text{ }an-r\text{ }br\]

 

Here\[n\text{ }=\text{ }12\] , \[a=\text{ }x2\] and \[b\text{ }=\text{ }-\text{ }y\text{ }x\]

 

Subbing the qualities we get

 

\[Tn+1\text{ }=12Cr\text{ }\times \text{ }x2\left( 12-r \right)\text{ }\left( -\text{ }1 \right)r\text{ }yr\text{ }xr\]

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Image 15

\[=\text{ }-\text{ }1r\text{ }12cr\text{ }.x24\text{ }\text{ }2r.\text{ }yr\]

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