This graph might represent a ball rebounding between two walls separated by two centimetres. Every two seconds, the ball bounces back and forth between the walls at a constant pace.
2 x 10-2)/2 = 0.01 m/s Velocity = displacement/time
Initial momentum = mu = 0.04 x 0.01 = 4 x 10-4 kgm/s Initial momentum = mu = 0.04 x 0.01 = 4 x 10-4 kgm/s
mv = 0.04 x (-0.01) = – 4 x 10-4 kgm/s Final momentum = mv = 0.04 x (-0.01) = – 4 x 10-4 kgm/s
The magnitude of the impulse is equal to the change in momentum.
8 x 10-4 kgm/s = (4 x 10-4 )-(- 4 x 10-4)
The ball receives an impulse every 2 seconds because the interval between two consecutive impulses is 2 seconds.