Verify $A(\operatorname{adj} \mathbf{A})=(\operatorname{adj} \mathbf{A}) \mathbf{A}=|\mathbf{A}| \mathbf{I}$ in $\left[\begin{array}{ccc}1 & -1 & 2 \\ 3 & 0 & -2 \\ 1 & 0 & 3\end{array}\right]$
Verify $A(\operatorname{adj} \mathbf{A})=(\operatorname{adj} \mathbf{A}) \mathbf{A}=|\mathbf{A}| \mathbf{I}$ in $\left[\begin{array}{ccc}1 & -1 & 2 \\ 3 & 0 & -2 \\ 1 & 0 & 3\end{array}\right]$

Let A = 

   

    = 

  

  

   

 adj. A = 

 A. (adj. A) = 

 ……….(i)

Again  (adj. A). A = 

  ……….(ii)

And 

Also  =     ……….(iii)

 From eq. (i), (ii) and (iii)  A. (adj. A) = (adj. A). A =