H2SO4 + 2NaOH → Na2SO4+ 2H2O
When 1L of 0.1M sulphuric acid solution is allowed to react with 1L of 0.1M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is
(i) 0.1 mol L-1
(ii) 7.10 g
(iii) 0.025 mol L-1
(iv) 3.55 g
Answer:
Correct Answers: (ii) 7.10 g; (iii) 0.025 mol L-1
Explanation:
Given,
0.1 mole of NaOH produces 0.05 mole
Mass of Na2SO4=0.05× (Molar mass of Na2SO4) = 7.10 g
Volume of the solution after mixing is 2 litres
Hence, Molarity of Na2SO4is 0.025 mol L−1