As indicated by the inquiry,
Think about tapered load,
Base Diameter = 9 cm
Thus, base range, r = 4.5 cm
Tallness, h = 3.5 cm
We realize that,
Inclination tallness,
The condition of volume of cone = 1/3πr2h
We realize that,
Volume of rice = Volume of tapered store
\[Volume\text{ }of\text{ }rice\text{ }=\text{ }1/3\pi \left( 4.5 \right)2\left( 3.5 \right)\]
We likewise realize that,
Material needs to simply cover store = Curved surface space of tapered load
What’s more, bended surface space of a cone = πrl
Accordingly, the material required \[=\text{ }\pi \left( 4.5 \right)\left( 5.7 \right)\text{ }=\text{ }80.61\text{ }cm2\text{ }\left[ appx \right]\]