Let the time taken by line to fill vessel = t minutes
Since water streams 10 m in 1 moment, it will stream 10t meters in t minutes.
As indicated by the inquiry,
Volume of funnel shaped vessel = Volume of water that goes through pipe in t minutes
Think about funnel shaped pope
Base Diameter = 40 cm
Base range, r = 20 cm
Tallness, h = 24 cm
We realize that the volume of cone = 1/3πr2h
Volume of cone shaped vessel \[=\text{ }1/3\pi \left( 20 \right)2\left( 24 \right)\text{ }=\text{ }3200\text{ }\pi \text{ }cm3\]
Think about barrel shaped line
Base width = 5 mm = 0.5 cm
Base span, r = 0.25 cm
Water covers 10t m distance in pipe,
Thus, we get,
Stature, h = 10t m = 1000t cm
We likewise realize that,
Volume of a chamber = πr2h
Volume of water passed in pipe \[=\text{ }\pi \left( 0.25 \right)2\left( 1000t \right)\text{ }=\text{ }62.5t\pi \text{ }cm3\]
In this way, we have
62.5tπ = 3200
62.5t = 3200
t = 51.2 minutes
We realize that,
0.2 minutes = 0.2(60) seconds = 12 seconds
Thusly, t = 51 minutes 12 seconds