Allow us first to work out the volume of barrel of pen that is of round and hollow shape
Think about barrel,
Since 1cm = 10 mm
Base width = 5 mm = 0.5 cm
Base span, r = 0.25 cm
Stature, h = 7 cm
We realize that,
Volume of a chamber = πr2h
Volume of barrel = π (0.25)27
Volume of barrel \[=\text{ }22/7\text{ }\times \text{ }0.25\text{ }\times \text{ }0.25\text{ }\times \text{ }7\text{ }=\text{ }1.375\text{ }cm3\]
Thus, as per the inquiry,
1.375 cm3 of ink can compose 3300 words
No of words that can be composed by 1 cm3 of ink = 3300/1.375 = 2400 words
1/fifth of a liter = 0.2 L
We realize that,
1 L = 1000 cm3
0.2 L = 200 cm3
Thus, no of words that can be composed by 200 cm3 = 2400(200) = 480000 words
In this way, 1/fifth of a liter ink can compose 480000 words.