Given

Harjyot deposited ₹ $27,500$ in a deposit scheme paying $12$%p.a.

Time, t = $3$years

C₁ = (P × r × t)/$100$

=$(27,500\times 12\times 1)/100$  

= ₹ $3,300$

P₁ = $27,500+3,300$

= ₹ $30,800$

C₂ = (P × r × t)/$100$

= $(30,800\times 12\times 1)/100$  

= ₹ $3,696$

P₂ = $30,800+3,696$  

= ₹ $34,496$

C₃ = (P × r × t)/$100$

= $(34,496\times 12\times 1)/100$

= ₹ $4139.52$

P₃ = $4,139.52+34,496$ 

= ₹ $38,636$

Solution:-

Then, the compound interest received by him = ₹ $3,300$+ ₹$3,696$+ ₹ $4,139.52$

= ₹ $11,135.52$