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AB is fixed line, so we need to state that the locus of the point P such that \[\angle APB={{90}^{\circ }}\]
AB is fixed line, so we need to state that the locus of the point P such that \[\angle APB={{90}^{\circ }}\]
Class 10 | Frank | Guides | ICSE | Loci | Maths
AB is fixed line, so we need to state that the locus of the point P such that \[\angle APB={{90}^{\circ }}\]

The locus of the point P such that \[\angle APB={{90}^{\circ }}\], with AB as diameter of the circle.

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