Benzene’s mass percent

$\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{\text { Mass of } C_{6} H_{6}}{\text { Total mass of the solution }} v \times 100$

$=\frac{\text { Mass of } C_{6} H_{6}}{\text { Mass of } C_{6} H_{6}+\text { Mass of } C C l_{4}} \times 100$

\[=\frac{22}{22+122}\times 100\]

\[=15.28%\]

Carbon Tetrachloride’s mass percent

$\left(\mathrm{CCl}_{4}\right)=\frac{\text { Mass of } C C l_{4}}{\text { Total mass of the solution }} \times 100$

$=\frac{\text{ Mass of }CC{{l}_{4}}}{\text{ Mass of }{{C}_{6}}{{H}_{6}}+\text{ Mass of }CC{{l}_{4}}}\times 100$

$=\frac{122}{22+122}\times 100$

$=84.72%$ $$.