(iii) Divya deposited Rs $1000$ at compound interest at the rate of $10%$ per annum. The amount at the end of first year, second year, third year, …, and so on.

An arithmetic progression is a number’s sequence such that the difference between the consecutive terms is constant.

Formula for this is: $an=d\left( n-1 \right)+c,$

(iii) Given,

Divya deposited $Rs1000$ at compound interest of $10%$ p.a

So, the amount at the end of first year is $=1000+0.1\left( 1000 \right)=Rs1100$

And, the amount at the end of second year is $=1100+0.1\left( 1100 \right)=Rs1210$

And, the amount at the end of third year is $=1210+0.1\left( 1210 \right)=Rs1331$

Cleary, these amounts $1100,1210$ and $1331$ are not in an A.P since the difference between them is not the same.