Solution:
R = {(a, b) : a ≤ b2} , Relation R is characterized as the arrangement of genuine numbers. (a, a) ∈ R then a ≤ a2 , which is bogus. R isn’t reflexive.
(a, b)=(b, a) ∈ R then a ≤ b2 and b ≤ a2, it is bogus articulation. R isn’t symmetric. Presently, a ≤ b2 and b ≤ c2,then a ≤ c2 , which is bogus. R isn’t transitive
In this way, R is neither reflexive, nor symmetric and nor transitive.