Arrangement:

Given information, n = 60

Middle of the given information = 28.5

Where, n/2 = 30

Middle class is 20 – 30 with an aggregate recurrence = 25+x

Lower cutoff of middle class, l = 20,

Cf = 5+x,

f = 20 and h = 10

Substitute the qualities

\[\begin{array}{*{35}{l}}

   28.5=20+\left( \left( 30-5-x \right)/20 \right)\text{ }\times \text{ }10  \\

   ~  \\

   8.5\text{ }=\text{ }\left( 25\text{ }\text{ }x \right)/2  \\

   ~  \\

   17\text{ }=\text{ }25-x  \\

\end{array}\]

Along these lines, x =8

Presently, from aggregate recurrence, we can recognize the worth of x + y as follows:

Since,

60=5+20+15+5+x+y

Presently, substitute the worth of x, to discover y

\[\begin{array}{*{35}{l}}

   ~  \\

   60\text{ }=\text{ }5+20+15+5+8+y  \\

   ~  \\

   y\text{ }=\text{ }60-53  \\

   ~  \\

   y\text{ }=\text{ }7  \\

\end{array}\] Along these lines, the worth of x = 8 and y = 7.