It is given in the question that,
$2.2d{{m}^{3}}$of brass is to be drawn into a cylindrical wire of Diameter $=0.25cm$
So, radius of the wire $(r)=d/2$
$=0.25/2=0.125*{{10}^{-2}}cm$
Then, $1cm=0.01m$
Therefore, $0.1cm=0.001m$
Assume the length of the wire be (h)
As we know that,
Volume of the cylinder $=\pi {{r}^{2}}h$
Volume of cylindrical wire $=$ Volume of brass of $2.2d{{m}^{3}}$
$\frac{22}{7}{{\left( 0.125\times {{10}^{-2}} \right)}^{2}}\times h=2.2\times {{10}^{-3}}$
$h=448m$
Therefore, the length of the cylindrical wire drawn is $448m$