SOLUTION:
Given:
f : R → R be the Signum Function characterized as
also, g : R → R be the Greatest Integer Function given by g (x) = [x], where [x] is
most prominent number not exactly or equivalent to x.
Presently, let say x ∈ (0, 1], then, at that point
[x] = 1 if x =1 and
[x] = 0 if 0< x < 1 Therefore:
Gof(x) = g(f(x)) = g(1) = [1] = 1
For x > 0
At the point when x ∈ (0, 1), then, at that point mist = 0 and gof = 1
In any case, mist (1) ≠ gof (1)
This shows that, haze and gof don’t concide in 90, 1].